Electric Fields and 3D Modeling (3/24/2015)

Redefining gravitational field definitions in terms of electrical fields.

Derived formula of an electric field.

2D representation of the electric field of a single charged particle. The point was to show how difficult it is to see on a board. 3D modeling will be used later.

More work and calculations done for the Calculating and Displaying the Electric Field of a Single Charged Particle lab. This is the Whiteboard Work part of the activity.

Work done for part 4 and 5 of the Electric Field lab. The coding for this activity is as follows:

from visual import *

## CONSTANTS

k = 9e9   ## OneOverFourPiEpsilonZero

q1 = 1.6e-19

## OBJECTS

particle = sphere(pos=vector(1e-10, 0, 0), radius = 2e-11, color=color.red)

xaxis = cylinder(pos=(-5e-10,0,0), axis=vector(10e-10,0,0),radius=.2e-11)

yaxis = cylinder(pos=(0,-5e-10,0), axis=vector(0,10e-10,0),radius=.2e-11)

zaxis = cylinder(pos=(0,0,-5e-10), axis=vector(0,0,10e-10),radius=.2e-11)

## the position of the arrow is the observation location:

Earrow1 = arrow(pos=vector(3.1e-10,-2.1e-10,0), axis = vector(1e-10,0,0), color=color.orange)

Earrow2 = arrow(pos=vector(3.1e-10,2.1e-10,0), axis = vector(1e-10,0,0), color=color.orange)

Earrow3 = arrow(pos=vector(-1.1e-10,-2.1e-10,0), axis = vector(1e-10,0,0), color=color.orange)

Earrow4 = arrow(pos=vector(-1.1e-10,2.1e-10,0), axis = vector(1e-10,0,0), color=color.orange)

Earrow5 = arrow(pos=vector(1e-10,0,3e-10), axis = vector(1e-10,0,0), color=color.orange)

Earrow6 = arrow(pos=vector(1e-10,0,-3e-10), axis = vector(1e-10,0,0), color=color.orange)

## CALCULATIONS

R1=Earrow1.pos-particle.pos

R2=Earrow2.pos-particle.pos

R3=Earrow3.pos-particle.pos

R4=Earrow4.pos-particle.pos

R5=Earrow5.pos-particle.pos

R6=Earrow6.pos-particle.pos

Ef1=((k*q1)/(mag(R1)**3))

Ef2=((k*q1)/(mag(R2)**3))

Ef3=((k*q1)/(mag(R3)**3))

Ef4=((k*q1)/(mag(R4)**3))

Ef5=((k*q1)/(mag(R5)**3))

Ef6=((k*q1)/(mag(R6)**3))

## write instructions below to tell the computer how to calculate the correct

## electric field E1 at the observation location (the position of Earrow1):

## change the axis of Earrow1 to point in the direction of the electric field at that location

## and scale it so it looks reasonable

scalefactor= 1e-20

Earrow1.axis= Ef1*R1*scalefactor

Earrow2.axis= Ef2*R2*scalefactor

Earrow3.axis= Ef3*R3*scalefactor

Earrow4.axis= Ef4*R4*scalefactor

Earrow5.axis= Ef5*R5*scalefactor

Earrow6.axis= Ef6*R6*scalefactor

print "Ef1: ", Ef1

print "Ef2: ", Ef2

print "Ef3: ", Ef3

print "Ef4: ", Ef4

print "Ef5: ", Ef5

print "Ef6: ", Ef6

## additional observation locations; do the same thing for each one

Work and calculations for the electric field from two point charges question.

Data from the excel portion of the problem shown four pictures above.

Work done answering the "Electric Field Due to a Differential Charge" activity.